Integrand size = 24, antiderivative size = 24 \[ \int \frac {1}{\sqrt {2-3 x} \sqrt {x} \sqrt {2+3 x}} \, dx=\sqrt {\frac {2}{3}} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{2}} \sqrt {x}\right ),-1\right ) \]
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Time = 0.00 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.042, Rules used = {116} \[ \int \frac {1}{\sqrt {2-3 x} \sqrt {x} \sqrt {2+3 x}} \, dx=\sqrt {\frac {2}{3}} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{2}} \sqrt {x}\right ),-1\right ) \]
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Rule 116
Rubi steps \begin{align*} \text {integral}& = \sqrt {\frac {2}{3}} F\left (\left .\sin ^{-1}\left (\sqrt {\frac {3}{2}} \sqrt {x}\right )\right |-1\right ) \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.02 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.96 \[ \int \frac {1}{\sqrt {2-3 x} \sqrt {x} \sqrt {2+3 x}} \, dx=\sqrt {x} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {5}{4},\frac {9 x^2}{4}\right ) \]
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Time = 0.63 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.21
method | result | size |
default | \(\frac {F\left (\frac {\sqrt {4+6 x}}{2}, \frac {\sqrt {2}}{2}\right ) \sqrt {3}\, \sqrt {-x}}{3 \sqrt {x}}\) | \(29\) |
elliptic | \(\frac {\sqrt {-x \left (9 x^{2}-4\right )}\, \sqrt {4+6 x}\, \sqrt {-6 x}\, F\left (\frac {\sqrt {4+6 x}}{2}, \frac {\sqrt {2}}{2}\right )}{6 \sqrt {x}\, \sqrt {2+3 x}\, \sqrt {-9 x^{3}+4 x}}\) | \(63\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.07 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.25 \[ \int \frac {1}{\sqrt {2-3 x} \sqrt {x} \sqrt {2+3 x}} \, dx=-\frac {2}{3} i \, {\rm weierstrassPInverse}\left (\frac {16}{9}, 0, x\right ) \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 78 vs. \(2 (19) = 38\).
Time = 10.76 (sec) , antiderivative size = 78, normalized size of antiderivative = 3.25 \[ \int \frac {1}{\sqrt {2-3 x} \sqrt {x} \sqrt {2+3 x}} \, dx=- \frac {\sqrt {6} {G_{6, 6}^{5, 3}\left (\begin {matrix} \frac {1}{2}, 1, 1 & \frac {3}{4}, \frac {3}{4}, \frac {5}{4} \\\frac {1}{4}, \frac {1}{2}, \frac {3}{4}, 1, \frac {5}{4} & 0 \end {matrix} \middle | {\frac {4 e^{- 2 i \pi }}{9 x^{2}}} \right )}}{24 \pi ^{\frac {3}{2}}} + \frac {\sqrt {6} {G_{6, 6}^{3, 5}\left (\begin {matrix} - \frac {1}{4}, 0, \frac {1}{4}, \frac {1}{2}, \frac {3}{4} & 1 \\0, \frac {1}{2}, 0 & - \frac {1}{4}, \frac {1}{4}, \frac {1}{4} \end {matrix} \middle | {\frac {4}{9 x^{2}}} \right )}}{24 \pi ^{\frac {3}{2}}} \]
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\[ \int \frac {1}{\sqrt {2-3 x} \sqrt {x} \sqrt {2+3 x}} \, dx=\int { \frac {1}{\sqrt {3 \, x + 2} \sqrt {x} \sqrt {-3 \, x + 2}} \,d x } \]
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\[ \int \frac {1}{\sqrt {2-3 x} \sqrt {x} \sqrt {2+3 x}} \, dx=\int { \frac {1}{\sqrt {3 \, x + 2} \sqrt {x} \sqrt {-3 \, x + 2}} \,d x } \]
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Timed out. \[ \int \frac {1}{\sqrt {2-3 x} \sqrt {x} \sqrt {2+3 x}} \, dx=\int \frac {1}{\sqrt {x}\,\sqrt {2-3\,x}\,\sqrt {3\,x+2}} \,d x \]
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